What is the method for calculating the value of bytes?

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Multiple Choice

What is the method for calculating the value of bytes?

Explanation:
The method for calculating the value of bytes is based on binary representation and weighting. When evaluating a byte, each bit within it is associated with a place value that corresponds to powers of two. In an 8-bit byte, the rightmost bit has a value of 2^0 (1), the next bit to the left represents 2^1 (2), continuing up to the leftmost bit which represents 2^7 (128). When calculating the overall value of a byte, you examine each bit: if the bit is set to 1, you add its corresponding place value to the total; if it is 0, you do not include that place value in the sum. This method accurately reflects the binary numbering system and allows you to determine the decimal equivalent of the binary pattern represented by the byte. For example, if a byte is represented as 10101010 in binary, you would calculate it as follows: - The first bit (from the right) is 0, contributing 0. - The second bit is 1 (2^1), adding 2 to the total. - The third bit is 0, contributing 0. - The fourth bit is 1 (2^3

The method for calculating the value of bytes is based on binary representation and weighting. When evaluating a byte, each bit within it is associated with a place value that corresponds to powers of two. In an 8-bit byte, the rightmost bit has a value of 2^0 (1), the next bit to the left represents 2^1 (2), continuing up to the leftmost bit which represents 2^7 (128).

When calculating the overall value of a byte, you examine each bit: if the bit is set to 1, you add its corresponding place value to the total; if it is 0, you do not include that place value in the sum. This method accurately reflects the binary numbering system and allows you to determine the decimal equivalent of the binary pattern represented by the byte.

For example, if a byte is represented as 10101010 in binary, you would calculate it as follows:

  • The first bit (from the right) is 0, contributing 0.

  • The second bit is 1 (2^1), adding 2 to the total.

  • The third bit is 0, contributing 0.

  • The fourth bit is 1 (2^3

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