In a binary system, how is the value of a byte determined?

In a binary system, how is the value of a byte determined?

• A. By adding up the values of its bits
• B. By taking the highest order bit
• C. By multiplying each bit by 10
• D. By dividing the total by 2

Answer: (A)

In a binary system, a byte consists of 8 bits, and the value of a byte is determined by adding up the values of its individual bits, where each bit represents a power of two. The bits are weighted from right to left, starting with \(2^0\) for the least significant bit and going up to \(2^7\) for the most significant bit. For instance, if the byte is represented as 10110101, the value can be calculated as follows: - The rightmost bit (1) represents \(2^0\) (1), - The next bit (0) represents \(2^1\) (0), - The third bit (1) represents \(2^2\) (4), - The fourth bit (1) represents \(2^3\) (8), - The fifth bit (0) represents \(2^4\) (0), - The sixth bit (1) represents \(2^5\) (32), - The seventh bit (0) represents \(2^6\) (0), - The leftmost bit (1) represents \(2^7\) (128). Adding these values together gives the total numerical value of the byte

In a binary system, a byte consists of 8 bits, and the value of a byte is determined by adding up the values of its individual bits, where each bit represents a power of two. The bits are weighted from right to left, starting with (2^0) for the least significant bit and going up to (2^7) for the most significant bit.

For instance, if the byte is represented as 10110101, the value can be calculated as follows:

• The rightmost bit (1) represents (2^0) (1),

• The next bit (0) represents (2^1) (0),

• The third bit (1) represents (2^2) (4),

• The fourth bit (1) represents (2^3) (8),

• The fifth bit (0) represents (2^4) (0),

• The sixth bit (1) represents (2^5) (32),

• The seventh bit (0) represents (2^6) (0),

• The leftmost bit (1) represents (2^7) (128).

Adding these values together gives the total numerical value of the byte